ich wollte euch kurz Fragen, ob ihr eine Idee habt, warum mein Koordinatenursprung "O" ungefähr viel zu groß ist.
\node[pos = 0.5pt, below] at (I) {$O$};
Viele Grüße
Henrik
P.s. Hier ist Quasi mein "nicht ganz Minimalbeispiel". Sorry.
\documentclass [ border = 2mm %papersize = A4 ]{standalone} \usepackage{pgfplots} \usepackage{tikz} \usetikzlibrary{arrows} \usepackage[english, ngerman]{babel} \usepackage{tikz-3dplot} \usepackage[active,tightpage]{preview} %generates a tightly fitting border around the work \PreviewEnvironment{tikzpicture} \setlength\PreviewBorder{2mm} \begin{document} \tdplotsetmaincoords{60}{60} \begin{tikzpicture}[scale=5,tdplot_main_coords] %Coodinate Setup \coordinate (I) at (0,0,0); \coordinate (S) at (1,1,1.25); %draw the main coordinate system axes \draw[thick,->] (0,0,0) -- (1,0,0) node[anchor=north east]{$x$}; \draw[thick,->] (0,0,0) -- (0,1,0) node[anchor=north west]{$y$}; \draw[thick,->] (0,0,0) -- (0,0,1) node[anchor=south]{$z$}; \node[pos = 0.5pt, below] at (I) {$O$}; \draw[thick,color=red,->] (I) -- (S) node[color = black, pos = 0.5, below = 1pt] {$\vec{r}_b$}; %Roteted Coordinatesystem Setup \tdplotsetrotatedcoords{0}{0}{0} \tdplotsetrotatedcoordsorigin{(S)} %Draw in Rotated System \draw[thick,tdplot_rotated_coords,->] (0,0,0) -- (.5,0,0) node[anchor=north west]{$x$}; \draw[thick,tdplot_rotated_coords,->] (0,0,0) -- (0,.5,0) node[anchor=west]{$y$}; \draw[thick,tdplot_rotated_coords,->] (0,0,0) -- (0,0,.5) node[anchor=south]{$z$}; \filldraw [thin, fill=gray, fill opacity=0.1, draw=black] plot [tdplot_rotated_coords,smooth cycle] coordinates {(.75,0,0) (0,.75,0) (0,0,.75) (0,-.5,0)}; \draw [tdplot_rotated_coords] node [below = 5pt] at (0,0,0) {$S$}; \draw [tdplot_rotated_coords] node [below = 5pt] at (.75,0,0) {$K_1$}; \end{tikzpicture} \end{document}