Habs nun so gelöst: \begin{eqnarray*}R1: \\DB(x_{R1})&=&(18-1/600\ x_{R1})\times x_{R1}-10.50 x_{R1}=7,50 x_{R1}-1/600\ {x_{R1}}^{2}\\DB(x_{R1})^{'}&=&7,50-1/300\ x_{R1}=0\Rightarrow x_{R1_{opt}}=2.250\ \mbox{Stück}\\R2: \\DB(x_{R2})&=&(32,50-1/400\ x_{R2})\times x_{R2}-19,50\ x_{R2}=13\ x_{R2}-1/40...