von Fruchtgnom » Mi 2. Feb 2022, 17:36
wenn ich ein wrappedd figure/ eine Graphic einfüge klappt alles, außer dass formeln in eigener Math umgebung welche nicht inline ist einfach über das bild hinausgehen.
\documentclass{amsart}
\usepackage[english]{babel}
\usepackage{graphicx}
\usepackage{amsmath, amsfonts, amsthm, geometry}
\usepackage[utf8]{inputenc} %kann sonderzeichen aus dem Text lesen
\usepackage{fancyhdr, lastpage} %Kopfzeile und referenz zur letzten Seite
\usepackage{wrapfig, framed, caption}
\newcommand{\R}{\mathbb{R}}
\newcommand{\C}{\mathbb{C}}
\newcommand{\PP}{\mathbb{P}}
\begin{document}
\section{The Shadow of a Cubic}
\begin{wrapfigure}[14]{r}{0.4\linewidth}
\begin{framed}\raggedleft%\centering
\rule{5cm}{4cm}
\caption{Fermat cubic}
\label{3linesferm}
\end{framed}
\end{wrapfigure}
It is a historical and remarkable fact, that any smooth Variety of degree $3$ in $\mathbb{P}^3$ contains exactly 27 lines. We call those Varieties Cubics and a line is a subvariety defined by two homogeneous polynomial of degree 1
\section{Theomrem}
There is exactly 27 lines on a smooth Cubic in $\mathbb{P}^3$.
\subsection{Proof}
To show this, we will use, that the fermat cubic $V(x_0^3+x_1^3+x_2^3+x_3^3)$ has exactly 27 lines. Afterwards we will show, that all smooth cubics have the same amount of lines. We will do that by showing, that
\begin{equation*}
\mathcal{M}=\{(X,L)|X \text{ is a smooth cubic}, L \text{ is a line in X} \} \subset U \times G(2,4),
\end{equation*} is a zarisky closed subset of...
The fermat cubic has 27 Lines.
\end{document}
Ich hoffe das minimalbeispiel funktioniert
wenn ich ein wrappedd figure/ eine Graphic einfüge klappt alles, außer dass formeln in eigener Math umgebung welche nicht inline ist einfach über das bild hinausgehen.
[code]
\documentclass{amsart}
\usepackage[english]{babel}
\usepackage{graphicx}
\usepackage{amsmath, amsfonts, amsthm, geometry}
\usepackage[utf8]{inputenc} %kann sonderzeichen aus dem Text lesen
\usepackage{fancyhdr, lastpage} %Kopfzeile und referenz zur letzten Seite
\usepackage{wrapfig, framed, caption}
\newcommand{\R}{\mathbb{R}}
\newcommand{\C}{\mathbb{C}}
\newcommand{\PP}{\mathbb{P}}
\begin{document}
\section{The Shadow of a Cubic}
\begin{wrapfigure}[14]{r}{0.4\linewidth}
\begin{framed}\raggedleft%\centering
\rule{5cm}{4cm}
\caption{Fermat cubic}
\label{3linesferm}
\end{framed}
\end{wrapfigure}
It is a historical and remarkable fact, that any smooth Variety of degree $3$ in $\mathbb{P}^3$ contains exactly 27 lines. We call those Varieties Cubics and a line is a subvariety defined by two homogeneous polynomial of degree 1
\section{Theomrem}
There is exactly 27 lines on a smooth Cubic in $\mathbb{P}^3$.
\subsection{Proof}
To show this, we will use, that the fermat cubic $V(x_0^3+x_1^3+x_2^3+x_3^3)$ has exactly 27 lines. Afterwards we will show, that all smooth cubics have the same amount of lines. We will do that by showing, that
\begin{equation*}
\mathcal{M}=\{(X,L)|X \text{ is a smooth cubic}, L \text{ is a line in X} \} \subset U \times G(2,4),
\end{equation*} is a zarisky closed subset of...
The fermat cubic has 27 Lines.
\end{document}
[/code]
Ich hoffe das minimalbeispiel funktioniert