LaTeX Forum

\documentclass[tikz, border=5pt]{standalone}
\usetikzlibrary{intersections,shapes.arrows}
 
\begin{document}
\begin{tikzpicture}[
  shading color/.style={top color=red,bottom color=green},
  arrow style/.style={
    single arrow, 
    shading color,
    minimum width=1cm, 
    minimum height=\pyramidHeight,
    draw
  }
]
  \newcommand{\labelShift}{5pt}
  \newcommand{\pyramidHeight}{5cm}
  \node [
    arrow style,
    anchor=west,
    rotate=90,
    label={[below=\labelShift]left:niedrig},
    label={[above=\labelShift]right:hoch}
  ] at (-6,0) {Komplexität der Implementierung};
  \node [
    arrow style,
    anchor=east,
    rotate=270,
    label={[above=\labelShift]left:niedrig},
    label={[below=\labelShift]right:hoch}
  ] at (6,0) {Kosten};
  
  \coordinate (A) at (-\pyramidHeight,0) {};
  \coordinate (B) at (\pyramidHeight,0) {};
  \coordinate (C) at (0,\pyramidHeight) {};

  \fill [shading color] (A) -- (B) -- (C) -- cycle;
  \draw[name path=AC] (A) -- (C);
  \draw[name path=BC] (B) -- (C);
  \foreach \y/\A in {0/TEST,1/TEST,2/TEST} {
    \path[name path=horiz] (A|-0,\y) -- (B|-0,\y);
    \draw[
      name intersections={of=AC and horiz,by=P},
      name intersections={of=BC and horiz,by=Q}
    ]
      (P) -- node[above] {\A} (Q)
    ;
  }
\end{tikzpicture}
\end{document}

\documentclass{article}
\usepackage{tikz}
\usetikzlibrary{intersections}
\usetikzlibrary{calc,trees,positioning,arrows,chains,shapes.geometric,%
	decorations.pathreplacing,decorations.pathmorphing,shapes,%
	matrix,shapes.symbols}
\begin{document}
	
\begin{figure}[h!]
	\begin{center}
		
		\begin{tikzpicture}
			
			
			
			\node [single arrow, minimum width=1cm, minimum height=5cm, draw, 
			anchor=west,rotate=90,top color=red,bottom color=green] at (-6,0) {Komplexität der Implementierung};
			\node [single arrow,, minimum width=1cm, minimum height=5cm, draw, 
			anchor=east,rotate=270] at (6,0) {Kosten};
			\node [single arrow,top color=red,bottom color=green, minimum width=1cm, minimum height=5cm, draw, 
			anchor=east,rotate=270] at (7,0) {Kosten};
			
			
			\coordinate (A) at (-5,0) {};
			\coordinate (B) at ( 5,0) {};
			\coordinate (C) at (0,5) {};
			\draw[name path=AC] (A) -- (C);
			\draw[name path=BC] (B) -- (C);
			\foreach \y/\A in 
			{0/TEST,
				1/TEST,
				2/TEST} {0/G,1/F,2/E,3/D,4/C,5/B,6/A
				\path[name path=horiz] (A|-0,\y) -- (B|-0,\y);
				\draw[name intersections={of=AC and horiz,by=P},
				name intersections={of=BC and horiz,by=Q},] (P) -- (Q)
				node[midway,above] {\A};
			}
		\end{tikzpicture}
		\caption{TEST}
		\label{fig:TEST}
	\end{center}
\end{figure}
\end{document}

\documentclass{article}
\usepackage{tikz}
\usetikzlibrary{intersections}
\usetikzlibrary{calc,trees,positioning,arrows,chains,shapes.geometric,%
	decorations.pathreplacing,decorations.pathmorphing,shapes,%
	matrix,shapes.symbols}
\begin{document}
	
	\begin{tikzpicture}
		
		
		\node [single arrow, minimum width=1cm, minimum height=5cm, draw, 
		anchor=west,rotate=90] at (-6,0) {Komplexität der Implementierung};
		\node [single arrow, minimum width=1cm, minimum height=5cm, draw, 
		anchor=east,rotate=270] at (6,0) {Kosten};
		
		
		\coordinate (A) at (-5,0) {};
		\coordinate (B) at ( 5,0) {};
		\coordinate (C) at (0,5) {};
		\draw[name path=AC] (A) -- (C);
		\draw[name path=BC] (B) -- (C);
		\foreach \y/\A in 
		{0/TEST,
			1/TEST,
			2/TEST} { %0/G,1/F,2/E,3/D,4/C,5/B,6/A
			\path[name path=horiz] (A|-0,\y) -- (B|-0,\y);
			\draw[name intersections={of=AC and horiz,by=P},
			name intersections={of=BC and horiz,by=Q}] (P) -- (Q)
			node[midway,above] {\A};
		}
	\end{tikzpicture}
\end{document}