LaTeX Forum

\documentclass{scrartcl}
\usepackage{selinput} 
\SelectInputMappings{adieresis={ä},germandbls={ß}} 
\usepackage{mathtools} 
\begin{document} 
\begin{flalign} 
  &\text{Stoke Gesetz:} 
  &\frac {U_{t} d_P \rho_G}{\eta_G}  
  &=\frac {Ar}{18} \quad\text{mit} \quad Re<0.4
  &\\
  %
  &\text{Übergangsgesetz:} 
  &\frac {U_{t} d_P \rho_G}{\eta_G}  
  &= {\frac {Ar}{7.5}}{0.666} \quad\text{mit} \quad 0.4<Re<500 
  &\\
  %
  &\text{Newton Gesetz:} 
  &\frac {U_{t} d_P \rho_G}{\eta_G}  
  &= {\frac {Ar}{0.33}}^{0.5} \quad\text{mit} \quad 500<Re
  & 
\end{flalign} 
\end{document}

\documentclass[fleqn]{scrartcl}
\usepackage{mathtools}
\begin{document}
\begin{align}
\intertext{Stoke Gesetz:}
\frac {U_{t} d_P \rho_G}{\eta_G}  &= 
\frac {Ar}{18} \quad\text{mit} \quad Re<0.4 \\
\intertext{\"Ubergangsgesetz:}
\frac {U_{t} d_P \rho_G}{\eta_G}  &= {
\frac {Ar}{7.5}}{0.666} \quad\text{mit} \quad 0.4<Re<500 \\
\intertext{Newton Gesetz:}
\frac {U_{t} d_P \rho_G}{\eta_G}  &= {
\frac {Ar}{0.33}}^{0.5} \quad\text{mit} \quad 500<Re
\end{align}

\begin{equation}
{\text Stoke Gesetz:} \qquad\qquad \frac {U_{t} d_P
\rho_G}{\eta_G}  = \frac
{Ar}{18} \quad\text{mit} \quad Re<0.4
\end{equation}
\begin{equation}
\text{Übergangsgesetz:}\qquad\qquad \frac {U_{t} d_P
\rho_G}{\eta_G}  = {\frac
{Ar}{7.5}}{0.666} \quad\text{mit} \quad 0.4<Re<500
\end{equation}
\begin{equation}
\text{Newton Gesetz:}\qquad\qquad \frac {U_{t} d_P
\rho_G}{\eta_G}  = {\frac
{Ar}{0.33}}^{0.5} \quad\text{mit} \quad 500<Re
\end{equation}
\end{document}

\documentclass[12pt,a4paper]{article}
\usepackage[latin1]{inputenc}
\usepackage[ngerman]{babel}
\usepackage{amsmath}
\usepackage{amsfonts}
\usepackage{amssymb}
\usepackage[left=2cm,right=2cm,top=2cm,bottom=2cm]{geometry}
\begin{document}
\begin{align}
{\text Stoke Gesetz:} \qquad\qquad \frac {U_{t} d_P \rho_G}{\eta_G}  &= \frac
{Ar}{18} \quad\text{mit} \quad Re<0.4\\
\text{Übergangsgesetz:}\qquad\qquad \frac {U_{t} d_P \rho_G}{\eta_G}  &= {\frac
{Ar}{7.5}}{0.666} \quad\text{mit} \quad 0.4<Re<500\\
\text{Newton Gesetz:}\qquad\qquad \frac {U_{t} d_P \rho_G}{\eta_G}  &= {\frac
{Ar}{0.33}}^{0.5} \quad\text{mit} \quad 500<Re
\end{align}
\end{document}

\begin{equation}
{\text Stoke Gesetz:} \qquad\qquad \frac {U_{t} d_P \rho_G}{\eta_G}  = \frac
{Ar}{18} \quad\text{mit} \quad Re<0.4
\end{equation}
\begin{equation}
\text{Übergangsgesetz:}\qquad\qquad \frac {U_{t} d_P \rho_G}{\eta_G}  = {\frac
{Ar}{7.5}}{0.666} \quad\text{mit} \quad 0.4<Re<500
\end{equation}
\begin{equation}
\text{Newton Gesetz:}\qquad\qquad \frac {U_{t} d_P \rho_G}{\eta_G}  = {\frac
{Ar}{0.33}}^{0.5} \quad\text{mit} \quad 500<Re
\end{equation}