LaTeX Forum

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\noindent Links:
\begin{flalign*} F&=\dot{m}_{0} \frac{\mu}{1+\mu} \left(w_{19}-c_0 \right)+A_{19} \left(p_{19}-p_0 \right) &\\
&+\dot{m}_0 \frac{1}{1+\mu} \left(w_{9}-c_0 \right)+A_9 \left(p_{9}-p_0
\right)-\dot{m}_0 ~ c_0 &\end{flalign*}
Zentriert:
\begin{align*} F&=\dot{m}_{0} \frac{\mu}{1+\mu} \left(w_{19}-c_0 \right)+A_{19} \left(p_{19}-p_0 \right) &\\
&+\dot{m}_0 \frac{1}{1+\mu} \left(w_{9}-c_0 \right)+A_9 \left(p_{9}-p_0 \right)-\dot{m}_0 ~ c_0 6\end{align*}
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\begin{flalign*}
F & =\dot{m}_{0} \frac{\mu}{1+\mu} \left(w_{19}-c_0 \right)+A_{19} \left(p_{19}-p_0 \right) &\\
& +\dot{m}_0 \frac{1}{1+\mu} \left(w_{9}-c_0 \right)+A_9 \left(p_{9}-p_0 \right)-\dot{m}_0 ~ c_0 &
\end{flalign*}

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\chapter{Hallo}

Für den Nettoschub eines Zweistromtriebwerks gilt 

\begin{equation}
F=\dot{m}_{19} \left(w_{19}-c_0 \right)+A_{19} \left(p_{19}-p_0 \right)+\dot{m}_9 \left(w_{9}-c_0 \right)+A_9 \left(p_{9}-p_0 \right)-\dot{m}_0 ~ c_0 
\end{equation} 

Sowie
\begin{equation}\label{Schub}
\begin{split}
F=\dot{m}_{0} \frac{\mu}{1+\mu} \left(w_{19}-c_0 \right)+A_{19} \left(p_{19}-p_0 \right) \\ +\dot{m}_0 \frac{1}{1+\mu} \left(w_{9}-c_0 \right)+A_9 \left(p_{9}-p_0 \right)-\dot{m}_0 ~ c_0 
\end{split}
\end{equation}

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\begin{flalign*} F=\dot{m}_{0} \frac{\mu}{1+\mu} \left(w_{19}-c_0 \right)+A_{19} \left(p_{19}-p_0 \right) \\ 
+\dot{m}_0 \frac{1}{1+\mu} \left(w_{9}-c_0 \right)+A_9 \left(p_{9}-p_0 \right)-\dot{m}_0 ~ c_0 \end{flalign*} 

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\begin{flalign*}
 E & = -\partial_{\beta} \ln (Z_K)&\\
 & = -\partial_{\beta} \ln \left( \frac{1}{h^{3N} N!} \left( A \frac{2\pi m}{\beta} \right)^N \right)&\\
 & = - \ln \left( \frac{1}{h^{3N} N!} \partial_{\beta} \left( A \frac{2\pi m}{\beta} \right)^N \right)&\\
 & = \frac{N}{\beta}&\\
 (& = N K_B T)&
 \end{flalign*}

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\begin{equation*}
\begin{split}
E & = -\partial_{\beta} \ln (Z_K)\\
& = -\partial_{\beta} \ln \left( \frac{1}{h^{3N} N!} \left( A \frac{2\pi m}{\beta} \right)^N \right)\\
& = - \ln \left( \frac{1}{h^{3N} N!} \partial_{\beta} \left( A \frac{2\pi m}{\beta} \right)^N \right) \\
& = \frac{N}{\beta}\\
& (= N K_B T)\\
\end{split}
\end{equation*}

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